ipx_addr.c revision 90868
1/*
2 * Copyright (c) 1986, 1993
3 *	The Regents of the University of California.  All rights reserved.
4 *
5 * This code is derived from software contributed to Berkeley by
6 * J.Q. Johnson.
7 *
8 * Redistribution and use in source and binary forms, with or without
9 * modification, are permitted provided that the following conditions
10 * are met:
11 * 1. Redistributions of source code must retain the above copyright
12 *    notice, this list of conditions and the following disclaimer.
13 * 2. Redistributions in binary form must reproduce the above copyright
14 *    notice, this list of conditions and the following disclaimer in the
15 *    documentation and/or other materials provided with the distribution.
16 * 3. All advertising materials mentioning features or use of this software
17 *    must display the following acknowledgement:
18 *	This product includes software developed by the University of
19 *	California, Berkeley and its contributors.
20 * 4. Neither the name of the University nor the names of its contributors
21 *    may be used to endorse or promote products derived from this software
22 *    without specific prior written permission.
23 *
24 * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
25 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
26 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
27 * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
28 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
29 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
30 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
31 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
32 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
33 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
34 * SUCH DAMAGE.
35 */
36
37#include <sys/cdefs.h>
38__FBSDID("$FreeBSD: head/lib/libipx/ipx_addr.c 90868 2002-02-18 20:35:27Z mike $");
39
40#if defined(LIBC_SCCS) && !defined(lint)
41static char sccsid[] = "@(#)ipx_addr.c";
42#endif /* LIBC_SCCS and not lint */
43
44#include <sys/param.h>
45#include <arpa/inet.h>
46#include <netipx/ipx.h>
47#include <stdio.h>
48#include <string.h>
49
50static struct ipx_addr addr, zero_addr;
51
52static void Field(), cvtbase();
53
54struct ipx_addr
55ipx_addr(name)
56	const char *name;
57{
58	char separator;
59	char *hostname, *socketname, *cp;
60	char buf[50];
61
62	(void)strncpy(buf, name, sizeof(buf) - 1);
63	buf[sizeof(buf) - 1] = '\0';
64
65	/*
66	 * First, figure out what he intends as a field separator.
67	 * Despite the way this routine is written, the preferred
68	 * form  2-272.AA001234H.01777, i.e. XDE standard.
69	 * Great efforts are made to ensure backwards compatibility.
70	 */
71	if ( (hostname = strchr(buf, '#')) )
72		separator = '#';
73	else {
74		hostname = strchr(buf, '.');
75		if ((cp = strchr(buf, ':')) &&
76		    ((hostname && cp < hostname) || (hostname == 0))) {
77			hostname = cp;
78			separator = ':';
79		} else
80			separator = '.';
81	}
82	if (hostname)
83		*hostname++ = 0;
84
85	addr = zero_addr;
86	Field(buf, addr.x_net.c_net, 4);
87	if (hostname == 0)
88		return (addr);  /* No separator means net only */
89
90	socketname = strchr(hostname, separator);
91	if (socketname) {
92		*socketname++ = 0;
93		Field(socketname, (u_char *)&addr.x_port, 2);
94	}
95
96	Field(hostname, addr.x_host.c_host, 6);
97
98	return (addr);
99}
100
101static void
102Field(buf, out, len)
103	char *buf;
104	u_char *out;
105	int len;
106{
107	register char *bp = buf;
108	int i, ibase, base16 = 0, base10 = 0, clen = 0;
109	int hb[6], *hp;
110	char *fmt;
111
112	/*
113	 * first try 2-273#2-852-151-014#socket
114	 */
115	if ((*buf != '-') &&
116	    (1 < (i = sscanf(buf, "%d-%d-%d-%d-%d",
117			&hb[0], &hb[1], &hb[2], &hb[3], &hb[4])))) {
118		cvtbase(1000L, 256, hb, i, out, len);
119		return;
120	}
121	/*
122	 * try form 8E1#0.0.AA.0.5E.E6#socket
123	 */
124	if (1 < (i = sscanf(buf,"%x.%x.%x.%x.%x.%x",
125			&hb[0], &hb[1], &hb[2], &hb[3], &hb[4], &hb[5]))) {
126		cvtbase(256L, 256, hb, i, out, len);
127		return;
128	}
129	/*
130	 * try form 8E1#0:0:AA:0:5E:E6#socket
131	 */
132	if (1 < (i = sscanf(buf,"%x:%x:%x:%x:%x:%x",
133			&hb[0], &hb[1], &hb[2], &hb[3], &hb[4], &hb[5]))) {
134		cvtbase(256L, 256, hb, i, out, len);
135		return;
136	}
137	/*
138	 * This is REALLY stretching it but there was a
139	 * comma notation separating shorts -- definitely non-standard
140	 */
141	if (1 < (i = sscanf(buf,"%x,%x,%x",
142			&hb[0], &hb[1], &hb[2]))) {
143		hb[0] = htons(hb[0]); hb[1] = htons(hb[1]);
144		hb[2] = htons(hb[2]);
145		cvtbase(65536L, 256, hb, i, out, len);
146		return;
147	}
148
149	/* Need to decide if base 10, 16 or 8 */
150	while (*bp) switch (*bp++) {
151
152	case '0': case '1': case '2': case '3': case '4': case '5':
153	case '6': case '7': case '-':
154		break;
155
156	case '8': case '9':
157		base10 = 1;
158		break;
159
160	case 'a': case 'b': case 'c': case 'd': case 'e': case 'f':
161	case 'A': case 'B': case 'C': case 'D': case 'E': case 'F':
162		base16 = 1;
163		break;
164
165	case 'x': case 'X':
166		*--bp = '0';
167		base16 = 1;
168		break;
169
170	case 'h': case 'H':
171		base16 = 1;
172		/* fall into */
173
174	default:
175		*--bp = 0; /* Ends Loop */
176	}
177	if (base16) {
178		fmt = "%3x";
179		ibase = 4096;
180	} else if (base10 == 0 && *buf == '0') {
181		fmt = "%3o";
182		ibase = 512;
183	} else {
184		fmt = "%3d";
185		ibase = 1000;
186	}
187
188	for (bp = buf; *bp++; ) clen++;
189	if (clen == 0) clen++;
190	if (clen > 18) clen = 18;
191	i = ((clen - 1) / 3) + 1;
192	bp = clen + buf - 3;
193	hp = hb + i - 1;
194
195	while (hp > hb) {
196		(void)sscanf(bp, fmt, hp);
197		bp[0] = 0;
198		hp--;
199		bp -= 3;
200	}
201	(void)sscanf(buf, fmt, hp);
202	cvtbase((long)ibase, 256, hb, i, out, len);
203}
204
205static void
206cvtbase(oldbase,newbase,input,inlen,result,reslen)
207	long oldbase;
208	int newbase;
209	int input[];
210	int inlen;
211	unsigned char result[];
212	int reslen;
213{
214	int d, e;
215	long sum;
216
217	e = 1;
218	while (e > 0 && reslen > 0) {
219		d = 0; e = 0; sum = 0;
220		/* long division: input=input/newbase */
221		while (d < inlen) {
222			sum = sum*oldbase + (long) input[d];
223			e += (sum > 0);
224			input[d++] = sum / newbase;
225			sum %= newbase;
226		}
227		result[--reslen] = sum;	/* accumulate remainder */
228	}
229	for (d=0; d < reslen; d++)
230		result[d] = 0;
231}
232