Lines Matching defs:have
17 You should have received a copy of the GNU General Public License
247 size_t have;
251 have = *bufend - *buf;
252 if (have > need)
256 want = need - have;
260 newbuf = (char *) bfd_realloc (*buf, (bfd_size_type) have + want);
264 *bufend = *buf + have + want;
923 /* The two BFD's have the same endianness, and we don't have
954 /* The two BFD's have different endianness, so we must swap
1478 that the information (the pointers and counts) in *DEBUG have been
1722 that have a least one procedure descriptor in them. The final
1746 if (fdr_ptr->cpd == 0) /* Skip FDRs that have no PDRs. */
1881 don't have it already. */
1914 (b) It is also possible for a PDR to have a *lower* vma than its associated
1931 Probably, a better solution would be to have a sorted PDR table. Each
1932 PDR would have a pointer to its FDR so file information could still be
1937 There is still at least one remaining issue. Sometimes a FDR can have a
1959 Since I don't have time to prepare a real fix for this right now, be
2018 file, even though their code may have been generated at
2036 to address ADDR. Thus, after invoking lookup(), we have a
2155 /* If fdr_ptr->rss is -1, then this file does not have full